Longest increasing subsequence - Dynamic programming

Problem Statement:

 The Longest Increasing Subsequence (LIS) problem is to find the length of the longest subsequence of a given sequence such that all elements of the subsequence are sorted in increasing order. For example, the length of LIS for {10, 22, 9, 33, 21, 50, 41, 60, 80} is 6 and LIS is {10, 22, 33, 50, 60, 80}.

/* Dynamic Programming Java implementation of LIS problem */
class LIS
{
    /* lis() returns the length of the longest increasing
       subsequence in arr[] of size n */
    static int lis(int arr[],int n)
    {
          int lis[] = new int[n];
          int i,j,max = 0;
          /* Initialize LIS values for all indexes */
           for ( i = 0; i < n; i++ )
              lis[i] = 1;
           /* Compute optimized LIS values in bottom up manner */
           for ( i = 1; i < n; i++ )
              for ( j = 0; j < i; j++ )
                         if ( arr[i] > arr[j] && lis[i] < lis[j] + 1)
                    lis[i] = lis[j] + 1;
           /* Pick maximum of all LIS values */
           for ( i = 0; i < n; i++ )
              if ( max < lis[i] )
                 max = lis[i];
            return max;
    }
    public static void main(String args[])
    {
        int arr[] = { 10, 22, 9, 33, 21, 50, 41, 60 };
            int n = arr.length;
            System.out.println("Length of lis is " + lis( arr, n ) + "\n" );
    }
}

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